Introduction to simple solutions math:
The simple solutions include the algebraic solutions using the simple operations like addition, finding the factors for the equation and also find the values for the linear equations. The simple solutions for the math include the basic operations for the complex numbers. The basic operations include the addition, subtraction, multiplication and also the division. Please express your views of this topic Absolute Value of a Complex Number by commenting on blog.
Examples for simple solutions math:
Example 1 for simple solutions math:
Find the value of x for the linear equation 2x +80 =12.
Solution:
The given linear equation is 2x +80 =12.
Subtract 80 on both sides of the equation to get the value of x.
2x+80-80 =12-80
2x= -68
x= -34
The value of x for the linear equation x+54 =10 is -34.
Example 2 for simple solutions math:
Find the values of x and y from the equation 2x+ 2y =5 and x - 2y = 10.
Solution:
The given equations are 2x+ 2y =5 and x - 2y = 10.
For finding the values for the equations, first remove x or y from the two equations.
2x+ 2y =5
x - 2y = 10
-----------------
3x =15
-----------------
Divide by 3 on both sides of the equation.
`(3x)/3` =`15/3`
x =5
Substitute the value of x in the equation (1) to get the value of y.
2 (5)+ 2y =5
10+ 2y =5
Subtract by 10 on both sides of the equation.
10+ 2y-10 =5-10
2y =-5
y =-`5/2`
The values of x and y for the equation 2x+ 2y =5 and x - 2y = 10 are x=5 and y=-`5/2` .
Example 3 for simple solutions math:
Find the value for the complex number (2+10i) + (3+16i).
Solution:
The given complex number is (2+10i) + (3+16i).
In this we have to add two complex numbers. Add the real part separately and add the imaginary part separately.
(2+10i) + (3+16i) = (2+3) + (10i + 16i)
(2+10i) + (3+16i) = 5 +26i
The value for the complex number (2+10i) + (3+16i) is 10+26i.
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Practice problem for simple solutions math:
Find the value for x+31= 182.
Answer: 151
Find the roots for the algebraic equation x2+5x +15=0.
Answer: x= -3, -5
The simple solutions include the algebraic solutions using the simple operations like addition, finding the factors for the equation and also find the values for the linear equations. The simple solutions for the math include the basic operations for the complex numbers. The basic operations include the addition, subtraction, multiplication and also the division. Please express your views of this topic Absolute Value of a Complex Number by commenting on blog.
Examples for simple solutions math:
Example 1 for simple solutions math:
Find the value of x for the linear equation 2x +80 =12.
Solution:
The given linear equation is 2x +80 =12.
Subtract 80 on both sides of the equation to get the value of x.
2x+80-80 =12-80
2x= -68
x= -34
The value of x for the linear equation x+54 =10 is -34.
Example 2 for simple solutions math:
Find the values of x and y from the equation 2x+ 2y =5 and x - 2y = 10.
Solution:
The given equations are 2x+ 2y =5 and x - 2y = 10.
For finding the values for the equations, first remove x or y from the two equations.
2x+ 2y =5
x - 2y = 10
-----------------
3x =15
-----------------
Divide by 3 on both sides of the equation.
`(3x)/3` =`15/3`
x =5
Substitute the value of x in the equation (1) to get the value of y.
2 (5)+ 2y =5
10+ 2y =5
Subtract by 10 on both sides of the equation.
10+ 2y-10 =5-10
2y =-5
y =-`5/2`
The values of x and y for the equation 2x+ 2y =5 and x - 2y = 10 are x=5 and y=-`5/2` .
Example 3 for simple solutions math:
Find the value for the complex number (2+10i) + (3+16i).
Solution:
The given complex number is (2+10i) + (3+16i).
In this we have to add two complex numbers. Add the real part separately and add the imaginary part separately.
(2+10i) + (3+16i) = (2+3) + (10i + 16i)
(2+10i) + (3+16i) = 5 +26i
The value for the complex number (2+10i) + (3+16i) is 10+26i.
Is this topic Images of Obtuse Angles hard for you? Watch out for my coming posts.
Practice problem for simple solutions math:
Find the value for x+31= 182.
Answer: 151
Find the roots for the algebraic equation x2+5x +15=0.
Answer: x= -3, -5
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