Math Number Activities

Introduction to math number activities:

Math number activities   is defined as understanding the concepts, ideas, problems concerning with different numbers according to their studies and practice. Math number sense is not a separate set of skills to be learned in a month or two, it is understand by daily practice and working with the problems.  Through math number, students can have interactive learning with animations. Math number activities learning are very comfortable and easy. Moreover, math number activities are one to one learning. Having problem with Multiplication of Rational Numbers keep reading my upcoming posts, i will try to help you.


Problems for math number activities:


Operations in math number activities:

Place value for number activities

Example1:

Find the place value of the underlined number 987.

Solution:

Here, 7 - 1's place

8 - 10's place

9 - 100's place.

Hence the number 9 is in 100's place

Example2:

Find the place value of the underlined number 1780.

Solution:

Here, 0 - 1's place

8 - 10's place

7 - 100's place.

1 - 1000's place

Hence the number 1 is in 1000's place.

Math number activities for Expanded form:

Example 1:

Write the given number in expanded form, 976.

Solution:

Here, the given number is in standard form,

The expanded form of the number is,

976 = 900 + 70 + 6.

Example 2:

Write the given number in expanded form, 2026.

Solution:

Here, the given number is in standard form,

The expanded form of the number is,

2026 = 2000 + 0 + 20 + 6

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Problems for math number activities:


Math number activities written form:

Example 1:

Write the given number in word form, 123.

Solution:

The given number is in standard form,

The word of the number is,

123 = One hundred and twenty three.

Example 2:

Write the given number in word form, 746.

Solution:

The given number is in standard form,

The word of the number is,

746= Seven hundred and forty six.

Example 3:

Write the given number in word form, 6026.

Solution:

The given number is in standard form,

The word of the number is,

6026= Six thousand twenty six.

Answers to Math Probelms

Introduction to math Problems:

The math is divided into the following main concepts they are

Algebra
Geometry
Probability


The basicfour mathematical opeartions are mainly used in mathematics. They are

Add
Sub
Multiply
Divide
In this topic we have to discuss about example problems for each topic in math.

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Example Problem in Algebra


The nine times of the number is subtracted from 63 and the resultant value is equal to 117. Find the answer for that unknown number.

Answer:

Let us assume that unknown number is the variable u. then nine times of the number is equal to 9u. And it is subtracted from 63 therefore 63 – 9u. Then this value is equivalent to 63 – 9u =117

The given algebraic expression can be written as

63 – 9u =117

Subtracting the value 9u on both sides we can get,

63 – 9u + 9u= 117 + 9u

That is 63 = 117 + 9u

Subtracting the value 117 on both sides we can get,

Then, 63-117 = 117 + 9u -117

That is -54 = 9u

Dividing the value 9 on both sides we can get,

-6 =u

This is the answer for u.

This is basic example of algebra problem.


Example Problem in Geometry


The angles in the quadrilateral shape are x, 2x, x, 2x find the measurement of the angles.

Answer:

The property says that the sum of the four angles in the quadrilateral is equal to the measurement of 360 degree.

Therefore we can written as,

X + 2x + x + 2x = 360 degree

That is 6x =360 degree

Dividing 6 on both sides we can get,

X= 60 degree

Therefore 2x = 120 degree

Then the angles of the quadrilaterals are 600, 1200 and 600, 1200

This is basic example of geometry problem. I have recently faced lot of problem while learning Non Isosceles Trapezoid, But thank to online resources of math which helped me to learn myself easily on net.


Example Problem in Probability


A coin is tossed at one time. Calculate the probability that the side of coin be head.

Answer:

Total probability of tossing a coin at a time = {H, T}

Therefore number of sample space =2

Find the probability of head = {H}

Therefore number of times event occurred =1

Therefore the probability = `(1)/(2)`

These are the basic math problems.

Business Math Equations

Introduction to business math equations:

Business mathematics is mathematics used by commercial enterprises to record and manage business operations. Commercial organizations use mathematics in accounting, inventory management, marketing, sales forecasting, and financial analysis. Mathematics typically used in commerce includes elementary arithmetic, elementary algebra, statistics and probability.(source : wikipedia)

In this article we are going to see some solved equations on business math and some practice questions on business math equations. Please express your views of this topic Compound Interest Equation by commenting on blog.


Solved questions on business math equations:


Question 1:

Total costs c(x) for producing one product is 1600 +1500x, and the entire profits can be represent by R(x) = 1600x - x2, what is the break even point and the maximum profit.

Solution:

Given, Total cost C(x) = 1600 + 1500x

Profit R(x) = 1600x - x2

At the break even points,

C(x) = R(x)

1600 + 1500x = 1600x - x2

x2 - 100x + 1600 = 0

It is in the quadratic equations form.

1600 (product)

/  \

-80   -20

\ /

-100 (sum)

x2- 100x + 1600 = 0

x2 - 80x -20x + 1600 = 0

x (x-80) - 20 (x - 80)=0

(x - 20)(x - 80) = 0

(x - 20) = 0

Add 20 on both sides, We get

x = 20

(x - 80) = 0,

Add 80 on both sides, We get

x = 80

x = 20, x = 80

Substitute x= 20 in c(x),

C (20) = 1600 + 1500 20 = 31600

Substitute x= 80 in c(x),

C (80) = 1600 + 1500 80 = 121600

The breakeven points are (20, 31600), (80, 121600)

The maximum profit R(80) = 1600(80) – (80)2

=   128000 – 6400

= 121600

The maximum profit is 121600.

Answer: The break even points are (20, 31600), (80, 121600)

The maximum profit is 121600.

Question 2:



John pays 125 dollar for his new dress includes the tax 10% . What is the original price of the new dress without tax?

Solution:

Given, Price of new dress with tax 10% is 125 dollar.

We need to find the original price.

Let us take the original price is x. We can form the equation as,

x + 10% x =125

x + 10x/100 = 125

x + x / 10 = 125

(10 x + x) / 10 = 125

Multiply by 10 on both sides,

11x = 1250

Divided by 11 on both sides,

x = (1250)/11

x = 113.63

Answer: The original price 113.63

Between, if you have problem on these topics Solving Absolute Value Equations, please browse expert math related websites for more help on Area of a Circle Equation .

Practice questions on business math equations:


Problems :

1. The price of   fish tank is 55 dollar includes the tax 10% . What is the original price of the fish tank without tax?

2.A total cost of the product is 500 + 90x and total profit for that product is 150x – x².  What is the break even point of the product

Answer:

1. 50

2.(50, 5000), (10, 1400)

Math Square

Introduction:

In geometry, square is a polygon with four equal sides and angles and also it is called regular quadrilateral. The term "square" is an either a square number (" is the square of ") or convex quadrilateral with sides of equal length that are positioned at right angles to each other that includes geometric figure.

A square is a special case of an isosceles trapezoid, parallelogram, quadrilateral, rectangle, rhombus, kite and trapezoid.

The diagonals of a square are perpendicular and bisect one another and also they bisect each pair of opposite angles. I like to share this Triangular Prism Surface Area with you all through my article.


Properties


A square is both a rectangle (equal angles) and a rhombus(equal sides) and therefore has all the properties of both these shapes, namely:

The diagonals of a square bisect to each other.
The diagonals of a square bisect it’s their angles.
The diagonals of a square are perpendicular.
Opposite sides of a square are both equal and parallel.
All four angles of a square are equal.
The diagonals of a square are equal.
If a figure is both a rhombus (equal edge lengths) and a rectangle (right angles), then it is a square. (Rhombus (four equal sides) + Rectangle (four equal angles) = Square)
If a circle is circumscribed around a given square, the area of the circle is π / 2 (about 1.57) times the area of the square.
If a circle is inscribed in the given square, the area of the circle is π / 4 (about 0.79) times the area of the square.
A given square has a larger area than any other quadrilateral with the same perimeter
A given square tiling is one of three regular tilings of the plane (the others are the equilateral triangle and the regular hexagon). Please express your views of this topic Volume of a Sphere Calculator by commenting on blog.

Formula


The area of square = (side) 2

The perimeter of square = 4*side

Diagonals of square=Sqrt (2)*side



Example: 1

To find the area of square with side length 5 cm.

Area= (side) 2

= (5) 2

=5*5

=25

Area=25 cm2

Example 2:

To find the perimeter of square with side length 10 feet.

Perimeter= 4*side

=4*10

=40

Perimeter=40cm

Holt Middle School Math

Introduction:

In this article, we are going to study math for middle school by online test. This is much helpful for the students to study the middle school math. Middle school online math test covers the following topics such as arithmetic operations, algebra, geometry and measurements. Online study for middle school math provides the step by step solutions to all problems. Online middle school math test to study is very interactive and fun to learn for the students. I like to share this Linear Equation Calculator with you all through my article.


Linear equation problem solving:


Methods of solving liner equations in one variable:

Add the same number on both the sides of the equation.
Subtract the same number from the both sides of the equation.
Multiply the both sides of the equation by the same number (other than zero)
Divide the both sides of the equation by the same number (other than zero).
Statements with problems:

The unknown quantities may be symbolized by say x,y,z
Translate the statements of the problem word by word (step by step) into mathematical statements, to the extent it is possible.
Look for the quantities, which are equal and write the equation by writing appropriate expressions for these quantities.
Solve the equation for the unknown.
Check, whether the solution satisfies the conditions given in the problem

Example problems:


Example 1: Solve: 1/3 x – 5/2=6

Solution:           1/3 x -5/2= 6

Or    3x -4x +10 = 2x + 6 – 8

or -x +10 = 2x – 2

Now by transposing 2 x from right side to the left side we have.

- x + 10 - 2x = -2

or - 3x = - 2 - 10

or - 3x = - 12

-1/3 - 3x =-1/3-12

or x = 4

Example 2: Solve : 3x -2(2x - 5) = 2 (x + 3) - 8

Solution :  Here the unknown quantity x appears on both sides. Thus before transposing we simplify the expressions of both the sides.

Thus, 3x - 2 (2x - 5) = 2(x + 3) -8

Thus x =9/8is the solution of the equation

Check: L.H.S. = 0.6x + 4/8

= 0.6  x 9/8 + 4/5

= 54/80 +4/5

= 27/40 + 4/5 = 59 /40

R.H.S. = 0.28 x + 1.16

= 0.28 ×9/8 + 116/100

=63/200 + 116/100

= 63 + 232/200

= 295/200

=59/40

Thus L.H.S. = R.H.S., Therefore, x=9/8

Thus x = 4 is the solution of the equation Check : L.H.S.

= 3x - 2 (2x - 5)

= 3×4 - 2(2×4 - 5)

= 12 - 2 (8 - 5)

= 12 - 2 × 3

= 12 - 6 = 6

R.H.S. = 2 (x+3) 8

= 2 (4+3) - 8

= 14 - 8 = 6

L.H.S. = R.H.S.

Hence x = 4 is the correct solution. Having problem with systems of linear equations in two variables keep reading my upcoming posts, i will try to help you.


Practice problems:


Problem 1: Collect like terms and simplify the given expression: 10m^2 – 9m + 5m – 4m^2 – 7m + 8

Answer : 6m^2 – 11m + 8

Problem 2: The curved surface area of a right circular cylinder of height 14 cm is 88 cm^2. Find the radius of the base of the cylinder.

Answer : 1 cm

Problem 3: Curved surface area of a cone is 308 cm^2 and its slant (h) height is 14 cm. find the radius (r) of the base.

Answer : 7cm

Problem 4: Solve 2x +6 = 10

Answer: 2

math solver step by step

Introduction to Math solver step by step:

Mathematics is defiend as the “Queen of science”. Problem solving is the major part of the mathematics. In solving those problems, step by step explanation about that problem are more preferable. Students can clearly understand about the problem by step by step solving. Step by step solving of the problem is more convenient in categories like algebra, polynomials, geometry, and number theory and so on. In mathematics, quadratic equation teaching is also easier by step by step process of solving. Is this topic What is an Expression in Algebra hard for you? Watch out for my coming posts.


Example of linear equation in math solver step by step:


Solve the equations in a step by step process:

x + 2y = 14, 3x + y = 11,

Solution: Let the given equations be identified as follows.

x + 2y  = 14 (1)
3x + y  = 11 (2)


Consider the equations (1) and (2)
(1)               x + 2y    = 14
(2) × 2        6x + 2y   = 22     (subtracting)
–5x           = – 8

Divide 5 on both sides,

-5x/5 = -8/5

x = 8/5

x = 1.6

Substitute x = 1.6 in equation 1.

X + 2y = 14

1.6 + 2y = 14

Subtract 1.6 on both sides,

1.6 – 1.6 + 2y = 14 – 1.6

2y = 12.4

Divide 2 on both sides,

2y/2 = 12.4

y = 6.2

The values are x = 1.6 and y = 6.2

I have recently faced lot of problem while learning Partial Fraction Problems, But thank to online resources of math which helped me to learn myself easily on net.


Examples to Algebra problem in math solver using step by step process:


Example 1 to Algebra problem in math solver using step by step process:

Solve: 7(x - 3) =2x + 3

Step 1: Expand the brackets

7x - 18 = 2x + 3

Step 2: Subtract the 2x from of the both side

7x - 18 - 2x = 2x + 3 - 2x

Step 3: Reduce two side of equation

5x - 18 = 3

Step 4: Add 18 to both of the side

5x - 18 + 18 = 3 + 18

Step 5: Reduce both side of the equation

5x = 21

Step 6: Divide both the side by the value 4

x = 21/5

x= 4.2

Example 2 for Algebra problem in math solver using step by step process:

Solve:                          4x + 3 = 3x + 17

Step 1: Subtract 3x from two sides

4x + 3 - 3x = 3x + 17 - 3x

Step 2: Simplify both the sides

x + 3 = 17

Step 3: Subtract 3 from two sides

x + 3 - 3 = 17 - 3

Step 4: Simplify both the sides

x = 14

Definition of Data Type

Introduction for data type:

Data is acknowledged or identified as information, which is the information collect from some of the issue or incidence. Data’s are getting from different types of sources. In any sources first we have to gathering the data, analyzing the data and making inferences from that data’s. Different types of data’s are used in data collections. It was collected with the helps to know about all the information of data. In this article we are going to explaining about definition of data types. I like to share this Percentage off Calculator with you all through my article.

Explanations for Data Definition & Data Types:
Definition of data:

Data is defined as, the information which are collected from standard basis, like survey and organizational sources.
In this data to be shortened, impute, edited, used and aggregate in production of officials from statistics.
Data types:

The important types of data are given below,

Primary data,
Secondary data,
Qualitative data, and
Quantitative data.
These four data’s are the important types of data’s. And these all has so many types of subordinates.

In this data types, data collecting methods are the important sources for the data’s. And these four types of data’s are gathering the information from various types of methods. Understanding equation solver algebra is always challenging for me but thanks to all math help websites to help me out.

Explanations for Types of Data:

1. Primary data:

The primary data is the data, which are collecting the information from foremost first hand information collection.
These types of primary data’s are mostly pure and original data’s.
The primary data types having three types of various types of collecting data’s.
Primary data collection sub types:
Data’s get from investigation,
Data’s get from personal inquiry, and
Data’s and information get from telephones.
2. Secondary data:

The secondary data is the data, which is collecting from the second hand.
In this type given data is already gathered from any other persons for some purpose, and it has available for the present issues.
And mostly these secondary data’s are not relevant and uncontaminated or original data.
Secondary data source types:
Data from official, and
Data from Semi-official.
3. Qualitative data:

The qualitative data is the major data in the data collection process data’s.
The qualitative data is which is the information gathered in a non statistical (numerical) form.
Qualitative data getting from:
The transcription of the interview process,
The notes taken from the field works,
Videos clippings, and tape and audio recordings,
Pictures and images, reporting papers and e-mail documents.
4. Quantitative data:

Information that can be collected and gathered or expressed with numerically, this type of data is frequently collected in experiment, manipulated and statistically analyzed.
Quantitative data getting from:
Quantitative data can be represent visually in graph and chart,
The production of models, theories and hypotheses,
The improvement of instruments and types for measurement,
Experimental manage and manipulation of variables,
Gather of empirical data, and modeling and examination of analyze data.
Evaluation of results.
These all are the definition and explanations for the types of data and data definition.