problem on time and speed

Topic :- Time and Speed


Time problems and speed problems are there in both math and Physics .Here is a simple math problem which help you to understand to how to find time when speed value is given . This problem solved
by using distance formula ,So first we find the distance based on which we get the time .

Question:-
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer:-
Let the time taken by the second cyclist to catch up the first be 'x' hours.

Then the time taken by the first to reach than the point wil be (x+3) hours.

Speed of the second cyclist=10 miles/hour.

So the distance covered =speed*time
= 10 * x = 10x miles

Speed of the first cyclist = 6 miles/hour

So distance covered = 6(x+3)
=(6x+18) miles

Now distnce covered by both are same .

So

10x = 6x+18
-6x   -6x
------------------
4x  =  18

4x     18
---- = ----
4      4

   18     9        1
x= ---- = ---- = 4----
   4     2         2

So the time taken by the second
cyclist = 4 hours 30 minutes

I hope you liked it ,For math help ,you can reply me