What are Edges in Math

Introduction to edges in math:

In math, what are edges?. The edges are created when two surfaces of objects are intersected. The two-dimensional and three-dimensional objects have one or more edges. We can also refer the edges as boundary of objects or sides of shape. For example the cube shape contains 12 edges by surface intersection.


Explanation for edges in math


Edges in math:

Edges are considered as connector that is connect the one-dimensional line segment and two zero dimensional objects in math. The edges form the closed figure as polygon.

What are lateral edges?

The solid’s lateral faces are created by edges is called as lateral edges. For example consider the pentagonal prism. It has five lateral faces and these faces are connected by five lateral edges.

What are vertices?

The vertices are created by intersection of two edges and it is also called as corner of the shape. For example if the object has six edges means the number of vertices are six. The edges of shape are used for identify the name of shape.

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More about edges in math

Examples for edges in math:

What are edges in square and rectangle?

The square and rectangle are considered as quadrilateral. The square has equal length for each sides. The number of sides in square and rectangle is four and these sides are intersect and creates a four edges.

Edges in triangle:

The equilateral triangle has three sides. These three sides are intersected and create a the three edges.

Edges in pentagon:

The five sided polygon is called as pentagon and these sides are connected as edges. So the pentagon has five edges.

Edges in hexagon:

The hexagon is regular polygon and it has six edges and six vertices.

We can find the area and volume of shape by using edges with respect to formula and also find the angles of each vertex is estimated.

Help in Math Now

Introduction to help in math now:

Online Tutoring is one of the best way for getting help in various subjects. Tutor Vista is the best choice for getting help not only in math but also in English and Science.

In this article of help in math now, several problems related to various branches of mathematics are given with their respective answer. In addition, several practice problems are given with answer key which helps for better understanding.


Get help in math now through examples:


Example 1:

Find the Mean of the given data set: { 8, 9, 21, 12 }

Solution:

Mean   =  ( 8 + 9 + 21 + 12 ) / 4

=  50 / 4

= 12.5

Answer: Mean  = 12.5

Example 2:

Find the volume of cylinder given the radius is 23 cm and 42 cm.

Solution:

Volume of cylinder = `pi` r2 h cubic units.

= (3.14) * 232 * 42

=  3.14 * 529 * 42

=  69764.52 cm3

Answer: Volume of cylinder = 69764.52 cm3

Example 3:

Find the area of the square with the side length of 12 cm.

Solution:

Area of square  =  ( a ) 2

= ( 9 )2

= 12 * 12

= 144 cm^2

Answer: Area of square =  144 cm^2

Example 4:

Find the area of a triangle through base of 4 m and a height of 2 m.

Solution:

Area of a triangle = ½ b h

= ½ ( 4 ) ( 2 )

= 0.5 * 4 * 2

= 4 m2

Answer: Area of triangle = 4 m2

Example 5:

Solve :  3 ( x + 3 ) = 30

Solution:

3( x + 3 )  =  30

x + ( 3 x 3 )  =  30

3x + 9  =  30

3x  =  21

x  =  7

Answer:  x =  7

Example 6:

Find lateral surface area of cone with radius 10 cm and slant height 20 cm.

Solution:

Given:  Radius r =10 cm

Slant height l = 20 cm

Lateral surface area  = `pi` r l   square units.

= 3.14 x 10 x 20

= 628 cm^2

Answer: Lateral surface area = 628 cm^2



Example 7:

Find the range of the data set { 5, 12, 43, 25, 41 }

Solution:

Here, The maximum value is 43

The minimum value is 5

Range  =  Maximum value – Minimum value

=  43 – 5

= 38

Answer: Range  = 38

Having problem with is the square root of 5 a rational number keep reading my upcoming posts, i will try to help you.

Get help in math now through practice problems:


1) Find the range of the data set { 25, 55, 29, 32, 19 }

Answer: 36

2) Find the area of the square with the side length of 17 cm.

Answer: 289 cm^2

3) Find the Mean of the given data set: { 2, 7, 8, 11 }

Answer: 7

4) Find lateral surface area of cone with radius 4 cm and slant height 12 cm.

Answer: 150.72 cm^2

How 2 Do Math Work

INTRODUCTION TO HOW 2 DO MATH WORK

How 2 do math work is nothing but doing math problems. The main importance of how 2 do math work is the sequence of steps we follow to solve the math problem. Solve math problems relates important role in our daily life. Everyone should know the importance of math and how 2 do math work. How 2 do math work depends on the topics of the math work we do. Every topic has different steps to do the problem. Some topics follow formula method. Problems of different topics have many logic's. Many chapters undergoes math. All the problems of math cannot be solved by same way.  Every problem has to be solved by using different methods, different steps, etc.

Please express your views of this topic Perimeter of a Square Formula by commenting on blog.

PROBLEMS ON HOW 2 DO MATH WORK


1. Find the area and perimeter of a square of the side a = 9cm

Solution

This problem is based on formula method.

The side of the square = 9 cm

Formula to calculate the area of the square = a^2 or (side * side)

Area of the square = 9 * 9

= 81 square centimeter.

Formula to calculate the perimeter of the square is 4* side

Perimeter of the given square = 4 * 9

= 36 cm

2. How 2 do math work of (5*7) + 9 – 8 / 2 *2 + 2

Solution

Here we work out this problem by using PEMDAS rule

35 + 9 – 8 / 2 * 2 + 2 ------------(Parenthesis first)

35 + 9 – 8 / 4 + 2------------------(No exponents so net multiplication)

35 + 9 – 2 +2 ---------------------(Division)

44-4---------------------------------(Addition)

40

3. How 2 do math work of Multiplication of 7.8 x 3.2

Solution

7.8

3.2 x

----------

156

234   +

-------------

2 4.96

--------------

The process is first multiply the once digit and then multiply the tens digit. After the multiplication add at last and count the number of digits after decimal point in the question and place the decimal digit counting from last digit. This is the process of how 2 do math work of this multiplication.

Understanding 7th grade math problems with answers is always challenging for me but thanks to all math help websites to help me out.

Practice problems on how 2 do math work

Multiply 78 * 51
Add 84569 + 45213
Divide 235 / 5
Answer

3978
129782
47

Math Term Relation

Introduction for math term relation:

When comparing (relate) the objects (human beings) the concept of relation becomes very important. In a similar fashion we connect two sets (set of objects) by means of relation.

Let A = {2, 5, 7} and B = {4, 6, 8}. Consider a subset of the Cartesian product. A × B = {(2,4), (2,6, (2,8), (5,6), (5,8, (7,8)} If R denotes the relation “is less than”, then 2R4 (since 2 < 4), 2R6, 2R8, 5R6, 5R8, 7R8. This gives R = {(2,4), (2,6, (2,8), (5,6), (5,8, (7,8)}. The relation is R from A to B. The math term relation example problems and practice problems are given below.

I like to share this Graphing Ordered Pairs with you all through my article.

Example problems for math term relation:


Example problem 1:

Give examples of relations of the following type

(i) Reflexive and transitive but not symmetric

(ii) Neither reflexive nor symmetric but transitive

(iii) Nither reflexive nor transitive but symmetric.

Solution:

(i) The given relation “a divisor of ” is reflexive and transitive but not symmetric on the set of M natural numbers.

(ii) Consider the given relation “is greater than” on N. Since a > a is not true, the relation is not reflexive. If a > b, then b R a is not true. The above example relation is transitive.

(iii) Consider the relation R = {(2,3), (3,2),(3,4),(4,3)} on the set A = {2,3,4}. Evidently R is not reflexive as (2,2), (3,3), (4,4) are not in R. Since (2,3) and (3,2) are in R, it is symmetric. It is not transitive as (2,3), (3,2) ? R, but (2,2) ? R.

Example problem 2:

Let M represents the set of integers. S on I is defined as a S b if a – b is an even integer. Prove that S is an equivalence relation.

Solution:

By definition a S b if a – b is an even integer. Since a – a = 0 is even, we have a S a. Hence S is reflexive. Let a S b so that a – b is an even integer.

But then b – a = – (a – b) is also even and so b R a. Hence S is symmetric. Let a S b, and b S c so that a – b and b – c are even integers. Then (a – c) = (a – b) + (b – c) is also an even integer. Hence S is transitive so that S is an equivalence relation.

These example problems are very helpful to study of math term relation.

Having problem with college level math help keep reading my upcoming posts, i will try to help you.

Practice problems for math term relation:


Practice problem 1:

Given that A = {6, 7, 8, 9, 10} and B = {2, 3, 4, 5}. Write down all ordered pairs (a, b) such that a is divisible by b and hence write down the set of ordered pairs given the relation ‘is a multiple of’ from A to B.

Answer: (6,2), (6,3), (8,2), (8,4), (9,3), (10,2), (10,5)

Practice problem 2:

In the set N of natural numbers, examine the kinds of relation given below

(i) If a^2 + b^2 is a perfect square, a R b

(ii) if a^2 = b, a R b.

Answer: (i) symmetric (ii) not a relation

Studying For Math

Introduction to studying math problems:

Mathematics is the studying of quantity, structure, space, and change. Mathematicians seek out patterns, formulate new conjectures, and establish truth by rigorous deduction from appropriately chosen axioms and definitions. Mathematics is used throughout the world as an essential tool in many fields, including natural science, engineering, medicine, and the social sciences. In this article we shall studying math problem with detailed solution. (Source: wikipedia)


Studying for math example problems


Example:

The diameter of a cylinder base is 18 cm and the height of the cylinder is 13 cm. Find the solid cylinder surface area.

Solution:

Radius of cylinder = 9 cm

Surface area of cylinder = 2πr (r + h)

=2x`22/7` x9x (9+13)

= 2x`22/7` x9x (22)

=2x3.142x198

=1244cm^2

Example:

Isolate the variable x in the equation

8x + 2y = 16.

Solution:

The following steps are used to isolate variable x in the given equation

Subtracting the value  2y from both sides of the equation

8x + 2y - 2y = 16 - 2y

Simplify the above equation it gives the equation as:

8x = 16 - 2y

Now to divide the equation both side by 8both sides of the equation
8x / 8 = (16 - 4y) / 8

x = (16 - 4y) / 8

Now we get the isolated x.

Example:

Find the volume of a cylinder the area of the base of the cylinder is 18 cm^2 and the height of the cylinder is 12 cm.

Solution:

Volume of cylinder = Area of base of cylinder x height of cylinder

= 18 cm^2 x 12 cm

= 216 cm^3

Problem:

Find the triangle perimeters, whose length of a triangle sides are 22 cm, 35 cm and 50 cm,

Solution:

Perimeter of triangle formula = a+ b+ c

a=22

b=35

c=50

Perimeter of triangle = 22 + 35 + 50 = 107

Therefore perimeter of triangle = 107

Is this topic Perimeter and Area of Similar Figures hard for you? Watch out for my coming posts.

Studying for math practice problems


Problem:

Find the volume of a cylinder the area of the base of the cylinder is 20 cm^2 and the height of the cylinder is 11 cm.

Answer:

220 cm^3

Problem:

Isolate the variable x in equation

6x + 4y = 12.

Answer:

x = (12 - 4y) / 8

Math Radicals Solver

Introduction to math radicals solver:

Radicals is a form of symbol which is used in the mathematics. It is shown that the radical  symbol as  root "v". The number inside the radical symbol which is called as the radicand of the radical value, for example if the given value is square root of `sqrtx` . The x is called as the radicand which is the number inside the radical symbol root "v". There are more number of rooting methods available depending upon the value we have. The roots are square root `sqrtx` , cube root `root(3)(x)` , Fourth root `root(4)(x)` this up to nth root `root(n)(x)` . Here we are going to see about the math radicals solver in different methods and the solved example problems on it.

I like to share this Rules of Radicals with you all through my article.

Math radicals solver - Some properties:


Radicals form - Representations:

Function `a^(1/n)` :

The radical exponent  `a^(1/n) = root(n)(a)`

If n has odd value then,

If a is positive value then the function  `a^(1/n)` is positive.

If a is negative value then the function `a^(1/n)` is negative.

If a is zero value then the function `a^(1/n)` is also zero

If n has even value then,

If a is positive value then the function `a^(1/n)` is positive.

If a is negative value then the function `a^(1/n)` is not a real number.

If a is zero value then the function`a^(1/n)` is also zero

Radical Expression:

`x^(1/n) = root(n)(x)`    it is n root of x value.

Relation between expression and Radical:

`(x^(1/n))^n`   is the relation between the expression and radical .

Radical Exponent of Product:

`root(n)(axxb) = (axxb)^(1/n) = root(n)(a)xxroot(n)(b) =a^(1/n) xx b^(1/n)`

Radical for a quotient:

`root(n)(a/b) = (a/b)^(1/n) = (root(n)(a))/(root(n)(b)) = a^(1/n)/b^(1/n)`

Radical of a fraction:

`msqrta^n = a^(n/m) `

I have recently faced lot of problem while learning Properties of Radicals, But thank to online resources of math which helped me to learn myself easily on net.

Math radicals Solver Example Problems:


Math radicals Solver - Problem 1:

Solve `root(4)(81)`

Solution:

solve the 4th root for the given function.

`root(4)(81)` = `(9^2)^(1/4)`

= `9^(2/4)`

=` 9^(1/2)`

= 3

Math radicals Solver - Problem 2:

Solve radical form for `sqrt645`

Solution:

The root value 645 is nearly equal to the square values between 25 and 26, because 252 = 625 and 262 = 676

Step 1: Divide 645 by 15.

`645 / 25` = 25.8

Step 2: Take average for 25.8 and 25.

` (25.8 +25)/2` =  25.4

Step 3: Divide 645 by 25.4

`645/25.4` = 25.3937008

Step 4: Take average for the 25.3937008 and 25.4

`( 25.3937008 + 25.4)/2 `  =  25.3968504

Step 5: Now check the above result by taking square

25.39685042 = 645.00001

This value is more or less equal to 645

If the value is not equal repeat the step 3 and step 4

Math Rules of Integers

Introduction to math rules of integers:

In mathematics, rules of integer is one interesting topics in number representation. Integer contains a set of numbers in which are positive integer, negative integer and zero. It contains complete entity or unit. In integer, there are no fractional parts. Integer performs different arithmetic operations such as addition, subtraction, multiplication and division. Let us solve some example problems using math rules of integers.

Example for integers:

287, -547, 0, 31, etc,

I like to share this Positive and Negative Integers with you all through my article.

Different math rules of integers:


Different math rules of integers are,

Rules of Integer Addition:

In addition, we use the same sign. If we add the same sign integer values then we get the same sign.

Positive integer + Positive integer    =   Positive integer

Negative integer + Negative integer  =    Negative integer

Otherwise, we use different signs. We subtract the different sign integer values then we get the largest absolute value.

Positive integer + Negative integer

Negative integer + Positive integer

Rules of Integer Subtraction:

In subtraction, we keep the first integer as same, change the subtraction sign to addition and change the second integers sign into its opposite then we follow the rule for integer addition.

Rules of Integer multiplication:

Like addition rule,

Positive integer  ×  Positive integer     =   Positive integer

Negative integer  ×  Negative integer   =  Positive integer

Positive integer   × Negative integer    =  Negative integer

Negative integer  ×  Positive integer    =  Negative integer

Rules of Integer Division:

Positive integer  ÷  Positive integer  =  Positive integer

Negative integer  ÷  Negative integer  =  Positive integer

Positive integer   ÷ Negative integer  =  Negative integer

Negative integer  ÷  Positive integer  =  Negative integer

Having problem with Adding Integers keep reading my upcoming posts, i will try to help you.

Example problems using math rules of integers:


Some example problems using math rules of integers are,

Example 1:

Using integer addition rule in math, solve the given integers

450 + 257

Solution:

Given two integer numbers are

450 + 257

Both are two positive integers so, the result is also a positive numbers

Here we add 450 into 257, and then we get the result

450 + 257

707

Solution to the given two integers is 707.

Example 2:

Using integer subtraction rule in math, solve the given integers

897 – 456

Solution:

Given two integer numbers are

897 – 456

Both are two positive integers so, the result is also a positive numbers

Here we subtract 897 into 456, and then we get the result

897 – 456

441

Solution to the given two integers is 441.

Example 3:

Using integer multiplication rule in math, solve the given integers

754 × 12

Solution:

Given two integer numbers are

754 × 12

Both are two positive integers so, the result is also a positive numbers

Here we multiply 754 into 12, and then we get the result

754 × 12

9048

Solution to the given two integers is 9048.

Example 4:

Using integer division rule in math, solve the given integers

45870 ÷ 30

Solution:

Given two integer numbers are

45870 ÷ 30

Both are two positive integers so, the result is also a positive numbers

Here we divide 45870 by 30, and then we get the result

45870 ÷ 30

1529

Solution to the given two integers is 1529.

Example 5:

Using integer multiplication rule in math, solve the given integers

- 720 × 18

Solution:

Given two integer numbers are

- 720 × 18

Given integer number has both positive integer and negative integer so, the result is a negative numbers

Here we multiply - 720 into 18, and then we get the result

- 720 × 18

- 40

Solution to the given two integers is -40.

Example 6:

Using integer addition rule in math, solve the given integers

- 42 + (- 85)

Solution:

Given two integer numbers are

- 42 + (- 85)

Both are two negative integers so, the result is also a negative numbers

Here we add -42 into -85, and then we get the result

-42 - 85

-127

Solution to the given two integers is -127