Monday, April 22, 2013

Math Radicals Solver

Introduction to math radicals solver:

Radicals is a form of symbol which is used in the mathematics. It is shown that the radical  symbol as  root "v". The number inside the radical symbol which is called as the radicand of the radical value, for example if the given value is square root of `sqrtx` . The x is called as the radicand which is the number inside the radical symbol root "v". There are more number of rooting methods available depending upon the value we have. The roots are square root `sqrtx` , cube root `root(3)(x)` , Fourth root `root(4)(x)` this up to nth root `root(n)(x)` . Here we are going to see about the math radicals solver in different methods and the solved example problems on it.

I like to share this Rules of Radicals with you all through my article.

Math radicals solver - Some properties:


Radicals form - Representations:

Function `a^(1/n)` :

The radical exponent  `a^(1/n) = root(n)(a)`

If n has odd value then,

If a is positive value then the function  `a^(1/n)` is positive.

If a is negative value then the function `a^(1/n)` is negative.

If a is zero value then the function `a^(1/n)` is also zero

If n has even value then,

If a is positive value then the function `a^(1/n)` is positive.

If a is negative value then the function `a^(1/n)` is not a real number.

If a is zero value then the function`a^(1/n)` is also zero

Radical Expression:

`x^(1/n) = root(n)(x)`    it is n root of x value.

Relation between expression and Radical:

`(x^(1/n))^n`   is the relation between the expression and radical .

Radical Exponent of Product:

`root(n)(axxb) = (axxb)^(1/n) = root(n)(a)xxroot(n)(b) =a^(1/n) xx b^(1/n)`

Radical for a quotient:

`root(n)(a/b) = (a/b)^(1/n) = (root(n)(a))/(root(n)(b)) = a^(1/n)/b^(1/n)`

Radical of a fraction:

`msqrta^n = a^(n/m) `

I have recently faced lot of problem while learning Properties of Radicals, But thank to online resources of math which helped me to learn myself easily on net.

Math radicals Solver Example Problems:


Math radicals Solver - Problem 1:

Solve `root(4)(81)`

Solution:

solve the 4th root for the given function.

`root(4)(81)` = `(9^2)^(1/4)`

= `9^(2/4)`

=` 9^(1/2)`

= 3

Math radicals Solver - Problem 2:

Solve radical form for `sqrt645`

Solution:

The root value 645 is nearly equal to the square values between 25 and 26, because 252 = 625 and 262 = 676

Step 1: Divide 645 by 15.

`645 / 25` = 25.8

Step 2: Take average for 25.8 and 25.

` (25.8 +25)/2` =  25.4

Step 3: Divide 645 by 25.4

`645/25.4` = 25.3937008

Step 4: Take average for the 25.3937008 and 25.4

`( 25.3937008 + 25.4)/2 `  =  25.3968504

Step 5: Now check the above result by taking square

25.39685042 = 645.00001

This value is more or less equal to 645

If the value is not equal repeat the step 3 and step 4

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