Front End Estimation Math

Introduction to front end estimation math:

The front end estimation is typically produces the earlier estimation of the addition or the difference than the answer formed through adding or subtracting rounded numbers for the estimation in the mathematics. It may give the closer estimated values for the actual estimation for the given problem.

In the front end estimation of math, one takes the two maximum digits of a number, and then put zeros on the other position values. This is supposed to create the earlier estimation rather than rounding and then addition numbers. In this article we shall discuss the front end estimation in the math.

How to Calculate an Addition by front End Estimation Math:

Add the digits of the two maximum place values

Plug in zeros for the other place values

Ex 1:  5596 + 3845 is estimated to be 9300 through front end estimation math(i.e. 5500 + 3800).

Ex 2: 5596 + 855 is estimated to be 6300 through front end estimation math(i.e. 5500 + 800).

Examples for front End Estimation:

Ex 1: 77 + 53 = 80 + 50 = 130

Sol: Make a note of that we are only adding the left the majority numbers (8 and 5)



31 + 68 = 30 + 70 = 100



77 - 52 = 80 - 50 = 30



88 - 42 = 90 - 40 = 50.



But the numbers contains the three digits; round it to the nearby hundred places earlier than adding the left the majority digits or numbers

Ex 2:    264 + 590 = 300 + 600 = 900.



Sol: Make the note of that the front end estimation for the every other numbers apart from the left the majority digits (3 and 6) are equivalent to zero and we only added the left the majority digits as stated before.



335 + 555 = 300 + 600 = 900
666 - 354 = 700 - 400 = 300
832 - 678 = 800 - 700 = 100.


But the numbers contains the four digits, so round it to the nearby thousand place earlier than adding the left the majority digits or numbers



Ex 3:  3354 + 2677 = 3000 + 3000 = 6000.



Sol: Make a note of that the other numbers apart from the left the majority digits (3 and 3) are equivalent to zero and we only added the left the majority digits as stated before

6687 - 3765 = 7000 - 4000 = 3000

4245 + 2897 = 4000 + 3000 = 7000

8501 - 5508 = 9000 - 6000 = 3000.

But the numbers contains the five digits; round it to the nearby ten thousand places before adding the left the majority digits or numbers

Ex 4:  59974 - 36799 = 60000 - 40000 = 20000.

Sol: Make a note of that the other numbers apart from the left the majority digits (6 and 4) are equivalent to zero and we only subtracted the left the majority digits as stated before

93113 + 48893 = 90000 + 50000 = 140000