Tuesday, October 16, 2012

Add Radical Numbers

Introduction to add radical numbers:

A square root of a number is said to be a radical number. Which is obtained by closing the numbers under add, subtract, multiply, and root extraction. A radical expression is containing a square root.  Radical is the (Sqrt) v symbol. That is used to denote square root, otherwise it is called as nth root. Here we have to go for add radical numbers, and how to work out addition of radical numbers.

Add Radical Numbers:

Add (Adding) radical expressions, which are containing radicals. Adding radicals are simple, when similar terms.

Similar terms:

If the radicals are similar terms means it has meet with following conditions.

The radical both have same index.
Both two radicals under the root sign is have identical quantities.
Any radicals, which are outside is same value.
Different terms:

If the radicals are different (not same) terms means it has meet with following conditions:

The radicals both are having same indexes.
The quantities which are under the radicals are different (not same), but both radicals need to simplify.
The outside variables are different (Not as same).

I am planning to write more post on Significant Figures Practice, Ratios and Proportions Word Problems. Keep checking my blog.

Example Problems for Add Radical Numbers:

Example 1:

Solve: v125 + v45. Add the radical numbers and find the answer.

Given: v125 + v45

First we have to simplify it. (125 = 25 * 5, and 45 = 9 * 5)

= v (25*5) + v (9*5)             (take common factor outside)

= 5v5 + 3v5

= 8v5.

Answer is: 8v5

Example 2:

Solve: v256 + v196. Add the radical numbers and find the answer.

Given: v256 + v196

Simplify the given terms, and we get (256 = 16* 16 and 196 = 14 * 14)

= v 16 * 16 + v 14 * 14                       (take common terms outside)

= 16 + 14

= 30

Answer is: 30

Example 3:

Solve: 2av3a3b3 + 3bv27a5b. Add the radical equation, and find the answer.

Solution:

Given: 2av3a3b3 + 3bv27a5b

Simplify it, and write it as separate,

= 2av3a2. a. b2.b + 3bv9.3a2. a2.a.b   (take common factors as outside) and write,

= 2a2bv3ab + 9a2bv3ab

Then we combine the co-efficient terms and we get 11a2bv3ab.

Answer is: 11a2bv3ab.

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