From geometry terms and definitions we know that,
Pythagoras' theorem is a relation in Euclidean geometry among the three sides of a right triangle (right-angled triangle in British English). It states:
Applying Pythagoras theorem to ΔACF
AF=√(9+9)=√18=√(2*9)=3√2
Now in ΔBAF
BF2 = AB2+AF2
= 32+(3√2)2
= 9+18
BF2=27
BF=√(9*3)= 3√3 units
Similar way we can also find length of base of isosceles triangle
Pythagoras' theorem is a relation in Euclidean geometry among the three sides of a right triangle (right-angled triangle in British English). It states:
In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle)
Let's see a heights and distances trigonometry problems
Applying Pythagoras theorem to ΔACF
AF=√(9+9)=√18=√(2*9)=3√2
Now in ΔBAF
BF2 = AB2+AF2
= 32+(3√2)2
= 9+18
BF2=27
BF=√(9*3)= 3√3 units
Similar way we can also find length of base of isosceles triangle
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